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9x^2+9x^2=25
We move all terms to the left:
9x^2+9x^2-(25)=0
We add all the numbers together, and all the variables
18x^2-25=0
a = 18; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·18·(-25)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{2}}{2*18}=\frac{0-30\sqrt{2}}{36} =-\frac{30\sqrt{2}}{36} =-\frac{5\sqrt{2}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{2}}{2*18}=\frac{0+30\sqrt{2}}{36} =\frac{30\sqrt{2}}{36} =\frac{5\sqrt{2}}{6} $
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